Google TW 面試趣 - Test Engineer, Android

以下是面試過程:

Interviewer: 恩~好 那我們開始吧 !

Me: .... (恩 好喔...

Vampire number: positive integer v that can be factored into two integers x*y,
where base-10 digits of v are equal to the set of base-10 digits of x and y. These two factors are called the fangs.
Examples:
688 = 86 x 8
1260 = 21 x 60
1530 = 30 x 51
125460 = 204 x 615 = 246 x 510
12546 = 246 x 51
Please implement a method to check if it is a vampire number.
boolean isVampire(int x, int y) {
[fill here]
}

Interviewer: 你習慣用什麼語言? 那你自己再改一下function格式~

Me: Python ~ 好喔

Me: 想問一下，怎麼樣的情況會構成Vampire Number?

Interviewer: 恩~你是哪邊看不懂嗎?

Me: 將題目翻成中文念了一遍給他聽~所以668 = 86 * 8 這應該要return True or False

Interviewer: 就是~兩個相成的數字相成之後的結果，x, y出現的數字個數應該是要一樣的~

Me: 哦~好 那我知道了 ! 我能用字串解嗎 ?

Interviewer: 可以!

[解法1]

# x = 86 y = 8 
num = "688"
string_factors = "868"
factors_count_list = [2, 1, 2]
num_count_list = [1, 2, 2]
return True (O)
=================================
# x = 68 y = 8
num = "554"
string_factors = "688"
factors_count_list = [0, 0, 0]
num_count_list = [0, 0, 0]
return True (X)

Interviewer: 你這想法有點奇特，既然都決定用字串解了，換個方式吧?

[解法2]

# x = 86 y = 8 
num = "688"
string_factors = "868"
factors_count_list = ["6", "8", "8"]
num_count_list = ["6", "8", "8"]
string_factor = "688"
string_num = "688"
return True (O)
=================================
# x = 68 y = 8
num = "554"
string_factors = "688"
factors_count_list = ["4", "5", "5"]
num_count_list = ["6", "8", "8"]
string_factor = "455"
string_num = "688"
return False (O)

Interviewer: (恩...看了一下)

Interviewer: 那對於這份工作還有什麼要問的嗎 ?

Me: 恩...在 Google Automation team 與 一般 QA 有什麼不一樣?

Interviewer: 一般 QA手動測試居多，Automation的話就可能需要自己 build code建立 CI 流程，release process都要自動化。

Me: 那目前你們是用什麼樣的 Framework在做 Testing ?

Interviewer: Google 內部有很多套 ~恩~

Me: Ok, 那會需要 BDD嗎 ? 或是寫 Gherkin語法把 test case變成是一個可執行的test case?

Interviewer: 你是說JUnit那種嗎 ? 如果是的話會阿~

Me: 恩...(眼看時間快到就沒再問了 XD

感想:

HR: 那整體面試的時間分配是如何呢? 
Me: 自我介紹 與 Live coding
HR: 自介完之後Interviewer有對於你的工作經驗做詢問嗎? 
Me: 恩...沒有就直接開始了~
HR: 恩...那題目你覺得如何呢? 與我給你的參考資料相比的話?
Me: 我覺得差不多但偏簡單一些~
Me: 那接下來的onsite interview流程會是如何?

這解法就是直接對數字count，之後判斷數字否一樣。

[數字解法] https://stackoverflow.com/questions/39432432/python-vampire-number

原來是一題 Hard … (煙~